Aldol condensation is a useful reaction mechanism that you will encounter towards the end of your organic chemistry career. It’s a useful mechanism because the steps are very similar to several other reactions that you’ll run into-like crossed aldol condensation, Claisen-Schmidt condensation, Claisen condensations, crossed Claisen condensations, and Dieckmann condensations. Pay attention to the electron arrows! I apologize in advance if they are unclear, my chemsketch program is not the best.
Mechanism Breakdown
We’re going to demonstrate aldol condensation with a molecule of acetaldehyde, which for those of you who hate nomenclature looks like this:
Mechanism Breakdown
We’re going to demonstrate aldol condensation with a molecule of acetaldehyde, which for those of you who hate nomenclature looks like this:
An aldol condensation happens in three steps with one intermediate resonance structure. The first step is the formation of the enolate anion (for which I will show the resonane structures). The second step is the addition of that enolate to another molecule of acetaldehyde. The third step is the protonation of the addition product to result in the aldol product. Ready? Take a deep breath. Here we go!
The first step in aldol condensation is forming the enolate anion. This particular example is base-catalyzed aldol condensation. We’ll go over acid-catalyzed in another posting. In base-catalyzed aldol condensation, OH- ions in solution will remove a proton from the methyl group next to the carbonyl carbon. (The carbonyl carbon is the one with the oxygen attached). This proton can be removed from the methyl group because of its proximity to the oxygen atom! Being near an oxygen atom tends to make protons more acidic, or more readily available to be removed. This combined with a strong base allows the methyl group to be deprotonated and an anion to be formed with water as a byproduct. Let’s look at the resonance stabilization of this anion!
This resonance stabilization is important because it confirms that the enolate anion is stable enough to carry on to the next step of the reaction. The fact that the electrons are delocalized between the CH2 and the oxygen lends it a bit of extra stability so that it won’t immediately be re-protonated. Now it’s time to look at the addition reaction of the enolate to another molecule of acetaldehyde.
In this step of the reaction the negatively charged enolate attacks the most electrophilic part of the second acetaldehyde molecule. This would be the carbonyl carbon, or the carbon directly attached to the oxygen! The enolate ion attacks the carbonyl carbon, which breaks the double bond to the oxygen and gives the oxygen an extra pair of electrons, leaving it negatively charged. We are so close to the product now, and the last step is stupid easy. Here it is!
In this last step, the negatively charged oxygen picks up a proton from water you have in solution, and the electrons from that proton are kicked back off onto the oxygen, thereby regenerating your base! Since the base is regenerated, this reaction is referred to as base-catalyzed. The final product’s structure gives us a clue as to why this is called an aldol reaction. It’s because the final product contains an aldehyde functional group and an alcohol functional group. Practice this reaction, and tune in next time (probably not next week as I will be on vacation) when we look at crossed aldol condensations!This post was made by Faith, @premedprobs01, a premed student in Colorado aspiring to become an MD working either in oncology or rural primary care internationally. Check out her original blog at www.goodandfaithfulservice.wordpress.com